In an ac circuit I = 100 sin(200 pi t). The t | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The given equation for current is $I = I_0 \sin(\omega t)$,where $I_0 = 100 	ext{ A}$ and $\omega = 200 \pi 	ext{ rad/s}$.To reach the peak valu

Vedclass · Accepted Answer

$\frac{1}{400} 	ext{ s}$

Vedclass · Answer

(D) The given equation for current is $I = I_0 \sin(\omega t)$,where $I_0 = 100 	ext{ A}$ and $\omega = 200 \pi 	ext{ rad/s}$.To reach the peak value,the phase $\omega t$ must be equal to $\frac{\pi}{2}$.So,$200 \pi t = \frac{\pi}{2}$.Solving for $t$: $t = \frac{\pi}{2 	imes 200 \pi} = \frac{1}{400} 	ext{ s}$.Alternatively,the time taken to reach the peak value is $\frac{T}{4}$,where $T$ is the time period.Since $\omega = \frac{2 \pi}{T} = 200 \pi$,we get $T = \frac{1}{100} 	ext{ s}$.Therefore,$t = \frac{1}{4} 	imes \frac{1}{100} = \frac{1}{400} 	ext{ s}$.

In an $ac$ circuit $I = 100 \sin(200 \pi t)$. The time required for the current to achieve its peak value will be

Similar Questions

Currents flowing in each of the following circuits $A$ and $B$ respectively are:

Example of a biodegradable polymer pair is

The species with spin only magnetic moment of $\sqrt{24} \ BM$ is

Aluminium reacts with $NaOH$ and forms compound '$X$'. If the coordination number of aluminium in '$X$' is $6$,the correct formula of $X$ is

The logical statement $[\sim(\sim p \vee q) \vee (p \wedge r)] \wedge (\sim q \wedge r)$ is equivalent to

Vedclass Test Series

Exam Paper Generator

Online Exam Module