In an $AC$ circuit,$V$ and $I$ are given by $V = 150 \sin(150t) \text{ V}$ and $I = 150 \sin(150t + \pi/3) \text{ A}$. The power dissipated in the circuit is: (in $\text{ W}$)

  • A
    $5625$
  • B
    $11250$
  • C
    $2812.5$
  • D
    $106$

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