In a Young's double slit experiment,$15$ fringes are observed on a small portion of the screen when light of wavelength $500 \; nm$ is used. Ten fringes are observed on the same section of the screen when another light source of wavelength $\lambda$ is used. Then the value of $\lambda$ is (in $nm$):
- A$750$
- B$600$
- C$625$
- D$700$
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In Young's double-slit experiment,the fringes are displaced by a distance $x$ when a glass plate of refractive index $1.5$ is introduced in the path of one of the beams. When this plate is replaced by another plate of the same thickness,the shift of fringes is $(3/2)x$. The refractive index of the second plate is
Difficult
View SolutionTwo coherent sources $P$ and $Q$ produce interference at point $A$ on the screen,where a dark band is formed between the $4^{\text{th}}$ and $5^{\text{th}}$ bright band. The wavelength of light used is $6000 \text{ Å}$. The path difference between $PA$ and $QA$ is:
In $\text{YDSE}$,$S_1$ and $S_2$ have the same intensity $I_0$. Column-$I$ shows the distance $x$ of a point $P$ from the central point $O$ on the screen,and Column-$II$ shows the intensity at $P$. Match Column-$I$ with Column-$II$. (Wavelength is $\lambda$)
Column-$I$ Column-$II$ $(A) x = \frac{D \lambda}{d}$ $(P) I_0$ $(B) x = \frac{D \lambda}{4d}$ $(Q) 2 I_0$ $(C) x = \frac{D \lambda}{3d}$ $(R) 3 I_0$ $(D) x = \frac{D \lambda}{6d}$ $(S) 4 I_0$
| Column-$I$ | Column-$II$ |
|---|---|
| $(A) x = \frac{D \lambda}{d}$ | $(P) I_0$ |
| $(B) x = \frac{D \lambda}{4d}$ | $(Q) 2 I_0$ |
| $(C) x = \frac{D \lambda}{3d}$ | $(R) 3 I_0$ |
| $(D) x = \frac{D \lambda}{6d}$ | $(S) 4 I_0$ |
Medium
View SolutionIn Young's double slit experiment,the intensity on the screen at a point where path difference is $\lambda$ is $K.$ What will be the intensity at the point where path difference is $\lambda /4$?
Medium
View SolutionHow is the interference pattern affected when violet light replaces sodium light?
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