In a triangle,if the angles are in the ratio | vedclass

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(B) Let the angles be $3x, 2x, x$. Since the sum of angles in a triangle is $180^{\circ}$,we have $3x + 2x + x = 180^{\circ}$. $6x = 180^{\circ} \Righ

Vedclass · Accepted Answer

$2: \sqrt{3}: 1$

Vedclass · Answer

(B) Let the angles be $3x, 2x, x$. Since the sum of angles in a triangle is $180^{\circ}$,we have $3x + 2x + x = 180^{\circ}$. $6x = 180^{\circ} \Rightarrow x = 30^{\circ}$. Thus,the angles are $A = 90^{\circ}, B = 60^{\circ}, C = 30^{\circ}$. Using the Sine Rule,the ratio of the sides $a: b: c$ is $\sin A: \sin B: \sin C$. $a: b: c = \sin 90^{\circ}: \sin 60^{\circ}: \sin 30^{\circ}$. $a: b: c = 1: \frac{\sqrt{3}}{2}: \frac{1}{2}$. Multiplying by $2$,we get $a: b: c = 2: \sqrt{3}: 1$.

In a triangle,if the angles are in the ratio $3: 2: 1$,then the ratio of its sides is

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