In a transistor,if the collector current is $98 \%$ of emitter current,then the ratio of the base and collector currents is

An $n-p-n$ transistor is connected in common-emitter configuration as shown in the figure. If the collector current is $5 \text{ mA}$,$V_{BE} = 0.6 \text{ V}$,$V_{CE} = 3 \text{ V}$,and the common-emitter current amplification factor $\beta = 50$,then the values of $R_1$ and $R_2$ are respectively.

In an $n-p-n$ transistor,$200$ electrons enter the emitter in $10^{-8} \ s$. If $1 \%$ of electrons are lost in the base,then the current that enters the emitter and the current amplification factor are respectively $\left[e=1.6 \times 10^{-19} \ C\right]$

For a $CE$ amplifier,the current gain is $60$. If the load resistance is $5 \times 10^3 \ \Omega$ and the input resistance is $5 \times 10^2 \ \Omega$,then the voltage gain is .......

To use a transistor as an amplifier,

The graph of the input characteristic of a common emitter amplifier is: