(C) Given: Current gain $\beta = 60$,Load resistance $R_L = 5 \times 10^3 \ \Omega$,Input resistance $r_i = 5 \times 10^2 \ \Omega$.The voltage gain $

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

(C) Given: Current gain $\beta = 60$,Load resistance $R_L = 5 \times 10^3 \ \Omega$,Input resistance $r_i = 5 \times 10^2 \ \Omega$.The voltage gain $A_V$ for a common emitter amplifier is given by the formula:$A_V = \beta \times \frac{R_L}{r_i}$Substituting the given values into the formula:$A_V = 60 \times \frac{5 \times 10^3}{5 \times 10^2}$$A_V = 60 \times 10 = 600$Therefore,the voltage gain is $600$.

Class 12 Physics Semiconductor Electronics Junction Transistor

Medium

For a $CE$ amplifier,the current gain is $60$. If the load resistance is $5 \times 10^3 \ \Omega$ and the input resistance is $5 \times 10^2 \ \Omega$,then the voltage gain is .......

A
$500$
B
$460$
C
$600$
D
$560$

Explore More

Browse All

Question Bank

All Subjects

Class 12 Questions

Class 12

Physics Questions

Chapter

Semiconductor Electronics

Subtopic

Junction Transistor

In an $N-P-N$ transistor circuit,the collector current is $10 \ mA$. If $90\%$ of the electrons emitted reach the collector,then the emitter current $(I_E)$ and base current $(I_B)$ are respectively:

Difficult

View Solution

In a common base transistor circuit,the current gain is $0.98$. On changing emitter current by $5.00 \,mA$,the change in collector current is ......... $mA$.

Easy

View Solution

When $NPN$ transistor is used as an amplifier,

EasyAIEEE 2004

View Solution

For a common emitter amplifier,the voltage gain is $50$,the input resistance is $200 \ \Omega$,and the output resistance is $400 \ \Omega$. The power gain of the amplifier will be:

Medium

View Solution

In an $n-p-n$ transistor,$10^{10}$ electrons enter the emitter in $10^{-6} \ s$. If $2\%$ of the electrons are lost in the base,the current amplification factor $\beta$ is:

Difficult

View Solution

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial

For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free

For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo

For a $CE$ amplifier,the current gain is $60$. If the load resistance is $5 \times 10^3 \ \Omega$ and the input resistance is $5 \times 10^2 \ \Omega$,then the voltage gain is .......

Similar Questions

In an $N-P-N$ transistor circuit,the collector current is $10 \ mA$. If $90\%$ of the electrons emitted reach the collector,then the emitter current $(I_E)$ and base current $(I_B)$ are respectively:

In a common base transistor circuit,the current gain is $0.98$. On changing emitter current by $5.00 \,mA$,the change in collector current is ......... $mA$.

When $NPN$ transistor is used as an amplifier,

For a common emitter amplifier,the voltage gain is $50$,the input resistance is $200 \ \Omega$,and the output resistance is $400 \ \Omega$. The power gain of the amplifier will be:

In an $n-p-n$ transistor,$10^{10}$ electrons enter the emitter in $10^{-6} \ s$. If $2\%$ of the electrons are lost in the base,the current amplification factor $\beta$ is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module