In a transistor amplifier,the base-emitter junction is forward-biased and the collector-emitter junction is reverse-biased. The current gain is defined as:

  • A
    $\frac{\Delta I_{E}}{\Delta I_{B}}$
  • B
    $\frac{\Delta I_{B}}{\Delta I_{E}}$
  • C
    $\frac{\Delta I_{B}}{\Delta I_{C}}$
  • D
    $\frac{\Delta I_{C}}{\Delta I_{B}}$

Explore More

Similar Questions

In the following circuit, a voltmeter $V$ is connected across a lamp $L$. What change would occur in the voltmeter reading if the resistance $R$ is reduced in value?

In the given common-emitter circuit, an $npn$ transistor with $\beta = 100$ is connected. What is the output voltage of the amplifier?

The current amplification factor of a transistor is $50$. In a $CE$ amplifier circuit, the collector resistance is $5 \, k\Omega$ and the input resistance is $1 \, k\Omega$. If the input voltage is $0.01 \, V$, the output voltage is ........ $V$.

For a given transistor amplifier circuit in $CE$ configuration with $V_{CC} = 1 \text{ V}$,$R_c = 1 \text{ k}\Omega$,$R_b = 100 \text{ k}\Omega$,and $\beta = 100$,the value of the base current $I_b$ is:

An $NPN$ transistor circuit is arranged as shown in the figure. It is:

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo