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(A) In the given circuit, the emitter-base junction of the $N-P-N$ transistor is forward-biased by the battery $V_{BB}$ through the resistance $R$.Whe

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Increases

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(A) In the given circuit, the emitter-base junction of the $N-P-N$ transistor is forward-biased by the battery $V_{BB}$ through the resistance $R$.When the value of resistance $R$ is reduced, the base current $i_b$ increases according to Ohm's law $(i_b = (V_{BB} - V_{BE})/R)$.Since the collector current $i_c$ is related to the base current by $i_c = \beta i_b$, an increase in $i_b$ leads to a significant increase in the collector current $i_c$.The lamp $L$ is in the collector circuit. The potential difference across the lamp $L$ is given by $V_L = V_{CC} - i_c R_L$, where $R_L$ is the resistance of the lamp. However, in this specific common-emitter configuration, as $i_c$ increases, the voltage drop across the lamp $L$ increases because the transistor conducts more current from the $V_{CC}$ source through the lamp.Therefore, the reading of the voltmeter $V$ connected across the lamp $L$ increases.

In the following circuit, a voltmeter $V$ is connected across a lamp $L$. What change would occur in the voltmeter reading if the resistance $R$ is reduced in value?

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