In a series $LCR$ circuit,$R$ represents the resistance of an electric bulb. If the frequency of the $A.C.$ supply is doubled,what should be the values of inductance $L$ and capacitance $C$ to maintain the same current?

In an $AC$ circuit,an inductor,a capacitor,and a resistor are connected in series with $X_{L} = R = X_{C}$. The impedance of this circuit is:

An oscillating circuit consists of a capacitor with capacitance $C = 10 \, \mu F$, a coil with inductance $L = 6.0 \, \mu H$, and active resistance $R = 10 \, \Omega$. The mean power that should be fed to the circuit to maintain undamped harmonic oscillations with an external driving source of frequency $f = 50 \, Hz$ and peak voltage $V_m = 280 \, V$ is:

With an increase in the frequency of an $A.C.$ supply,the impedance of an $L-C-R$ series circuit

In a circuit,$L$,$C$,and $R$ are connected in series with an alternating voltage source of frequency $f$. When the current in the circuit leads the voltage by $45^{\circ}$,the value of $C$ is

In a series resonant circuit,the $ac$ voltage across resistance $R$,inductance $L$,and capacitance $C$ are $5\, V$,$10\, V$,and $10\, V$ respectively. The $ac$ voltage applied to the circuit will be.....$V$.