In a series $LCR$ resonance circuit,if we change the resistance only,from a lower to higher value:

  • A
    The bandwidth of the resonance circuit will increase.
  • B
    The resonance frequency will increase.
  • C
    The quality factor will increase.
  • D
    The quality factor and the resonance frequency will remain constant.

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Similar Questions

Match List-$I$ with List-$II$ :
List-$I$List-$II$
$(a)$ $\omega L > \frac{1}{\omega C}$$(i)$ Current is in phase with $emf$
$(b)$ $\omega L = \frac{1}{\omega C}$$(ii)$ Current lags behind the applied $emf$
$(c)$ $\omega L < \frac{1}{\omega C}$$(iii)$ Maximum current occurs
$(d)$ Resonant frequency$(iv)$ Current leads the $emf$

Choose the correct answer from the options given below :

An inductance of $2 \text{ mH}$,a capacitor of $20 \mu\text{F}$,and a resistance of $50 \Omega$ are connected in series to an $A.C.$ source. The reactance of the inductor and the capacitor are the same. The reactance of either of them will be: (in $Omega$)

An inductor of inductance $2\,\mu\text{H}$ is connected in series with a resistance,a variable capacitor,and an $AC$ source of frequency $7\,\text{kHz}$. The value of capacitance for which maximum current is drawn into the circuit is $\frac{1}{x}\text{ F}$,where the value of $x$ is $.........$. (Take $\pi = \frac{22}{7}$)

$A$ resistor of $50 \Omega$,an inductor of self-inductance $(\frac{2}{\pi^2}) \text{ H}$,and a capacitor of unknown capacity are connected in series to an $A$.$C$. source of $100 \text{ V}, 50 \text{ Hz}$. When the voltage and current are in phase,the value of the capacitance is: (in $\mu \text{F}$)

In a series $LCR$ circuit,a resistor of $300 \ \Omega$,a capacitor of $25 \ \text{nF}$ and an inductor of $100 \ \text{mH}$ are used. For maximum current in the circuit,the angular frequency of the ac source is $. . . . \times 10^4 \ \text{rad s}^{-1}$.

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