What happens to the mass number and atomic number of an element when it emits $\gamma$-radiation?
Mass number increases by four and atomic number increases by two.
Mass number decreases by four and atomic number decreases by two.
Mass number and atomic number remain unchanged.
Mass number remains unchanged while atomic number decreases by one.
How many alpha and beta particles are emitted when Uranium ${ }_{92} U ^{238}$ decays to lead ${ }_{82} Pb ^{206}$ ?
A nucleus of an element ${}_{84}{X^{202}}$ emits an $\alpha $-particle first, $\beta $ -particle next and then a gamma photon. The final nucleus formed has an atomic number
A radioactive nucleus undergoes $\alpha$- emission to form a stable element. What will be the recoil velocity of the daughter nucleus if $V$ is the velocity of $\alpha$-emission and $A$ is the atomic mass of radioactive nucleus
A radioactive nucleus undergoes a series of decay according to the scheme
$A\xrightarrow{\alpha }{{A}_{1}}\xrightarrow{\beta }{{A}_{2}}\xrightarrow{\alpha }{{A}_{3}}\xrightarrow{\gamma }{{A}_{4}}$
If the mass number and atomic number of $A$ are $180$ and $72$ respectively, then what are these number for $A_4$
A free neutron decays into a proton but a free proton does not decay into neutron. This is because