What happens to the mass number and atomic number of an element when it emits $\gamma$-radiation?
- AMass number increases by four and atomic number increases by two.
- BMass number decreases by four and atomic number decreases by two.
- CMass number and atomic number remain unchanged.
- DMass number remains unchanged while atomic number decreases by one.
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Similar Questions
$A$ nucleus $X$ undergoes the following transformation:
$X \xrightarrow{\alpha} Y$
$Y \xrightarrow{2\beta} Z$
Then:
$X \xrightarrow{\alpha} Y$
$Y \xrightarrow{2\beta} Z$
Then:
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View SolutionIn the radioactive disintegration series,for the process $_{92}^{238}U \xrightarrow{\alpha} X \xrightarrow{\beta^-} {}_{Z}^{A}Y$,the values of $Z$ and $A$ respectively are:
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View SolutionIn the uranium radioactive series,the initial nucleus is $_{92}U^{238}$ and the final nucleus is $_{82}Pb^{206}$. When the uranium nucleus decays to lead,the number of $\alpha$-particles emitted is $x$ and the number of $\beta$-particles emitted is $y$. Find $x$ and $y$.
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View SolutionIn a radioactive decay chain,the initial nucleus is ${}_{90}^{232}Th$. At the end,$6$ $\alpha$-particles and $4$ $\beta$-particles are emitted. If the final nucleus is ${}_{Z}^{A}X$,then $A$ and $Z$ are given by:
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