What happens to the mass number and atomic number of an element when it emits $\gamma$-radiation?
Mass number increases by four and atomic number increases by two.
Mass number decreases by four and atomic number decreases by two.
Mass number and atomic number remain unchanged.
Mass number remains unchanged while atomic number decreases by one.
In the given nuclear reaction, how many $\beta$ and $\alpha$ particles are emitted $_{92}{X^{235}} \to {\;_{82}}{Y^{207}}$
In the following nuclear rection, $D \stackrel{\alpha}{\longrightarrow} D _{1} \stackrel{\beta-}{\longrightarrow} D _{2} \stackrel{\alpha}{\longrightarrow} D _{3} \stackrel{\gamma}{\longrightarrow} D _{4}$ Mass number of $D$ is $182$ and atomic number is $74$ . Mass number and atomic number of $D _{4}$ respectively will be
Which can pass through $20 \,cm$ thickness of the steel
Assertion: ${}_Z{X^A}$ undergoes a $2\alpha -$ decays, $2\beta -$ decays and $2\gamma - $ decays and the daughter product is ${}_{Z - 2}{X^{A - 8}}$
Reason : In $\alpha - $decays the mass number decreases by $4$ and atomic number decreases by $2$. In $2\beta - $ decays the mass number remains unchanged, but atomic number increases by $1$ only.
If Alpha, Beta and Gamma rays carry same momentum, which has the longest wavelength