In a race of 200,m,A can beat B by 31,m and C | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) In a $200\,m$ race,when $A$ covers $200\,m$,$B$ covers $(200 - 31) = 169\,m$ and $C$ covers $(200 - 18) = 182\,m$.Thus,the ratio of speeds is $A:B

Vedclass · Accepted Answer

$20$

Vedclass · Answer

(B) In a $200\,m$ race,when $A$ covers $200\,m$,$B$ covers $(200 - 31) = 169\,m$ and $C$ covers $(200 - 18) = 182\,m$.Thus,the ratio of speeds is $A:B:C = 200:169:182$.To find how much $C$ beats $B$ by,we compare $C$ and $B$: $\frac{C}{B} = \frac{182}{169}$.This means when $C$ covers $182\,m$,$B$ covers $169\,m$,so $C$ beats $B$ by $(182 - 169) = 13\,m$ in a $182\,m$ race.In a $280\,m$ race,the distance by which $C$ beats $B$ is calculated as: $	ext{Gain} = \left(\frac{13}{182}ight) 	imes 280 = \frac{1}{14} 	imes 280 = 20\,m$.Therefore,$C$ will beat $B$ by $20\,m$.

In a race of $200\,m$,$A$ can beat $B$ by $31\,m$ and $C$ by $18\,m$. In a race of $280\,m$,$C$ will beat $B$ by (in $m$):

Similar Questions

In a game of $100$ points,$A$ can give $B$ $20$ points and $C$ $28$ points. The number of points $B$ can give $C$ in a game of $100$ points is:

In a $1\, km$ race, $A$ beats $B$ by $25\, m$ or $5\, s$. Find the time taken by $A$ to complete the race.

In a $500\, m$ race,the ratio of speeds of two contestants $A$ and $B$ is $3: 4$. $A$ has a start of $140\, m$. Then,$A$ wins by (in $m$)

In a $1000\, m$ race,$A$ beats $B$ by $100\, m$ and $C$ by $200\, m$. By how many meters can $B$ beat $C$ in a race of $1350\, m$?

In a race of $600 \, m$,$A$ can beat $B$ by $60 \, m$ and in a race of $500 \, m$,$B$ can beat $C$ by $50 \, m$. By how many meters will $A$ beat $C$ in a race of $400 \, m$?

Vedclass Test Series

Exam Paper Generator

Online Exam Module