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(C) To reach the winning post,$A$ will have to cover a distance of $(500 - 140) = 360\, m$.The ratio of speeds of $A$ and $B$ is $3:4$. This means tha

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$20$

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(C) To reach the winning post,$A$ will have to cover a distance of $(500 - 140) = 360\, m$.The ratio of speeds of $A$ and $B$ is $3:4$. This means that while $A$ covers $3\, m$,$B$ covers $4\, m$.When $A$ covers $360\, m$,the distance covered by $B$ is calculated as:Distance covered by $B = \frac{4}{3} 	imes 360 = 480\, m$.Since the total race distance is $500\, m$,$B$ is at a distance of $(500 - 480) = 20\, m$ from the winning post when $A$ reaches it.Therefore,$A$ wins by $20\, m$.

In a $500\, m$ race,the ratio of speeds of two contestants $A$ and $B$ is $3: 4$. $A$ has a start of $140\, m$. Then,$A$ wins by (in $m$)

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