In a plane,there are 10 points,out of which 4 | vedclass

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(B) To form a triangle,we need $3$ non-collinear points.Total number of ways to select $3$ points out of $10$ is given by $^{10}C_3$.$^{10}C_3 = \frac

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$116$

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(B) To form a triangle,we need $3$ non-collinear points.Total number of ways to select $3$ points out of $10$ is given by $^{10}C_3$.$^{10}C_3 = \frac{10 	imes 9 	imes 8}{3 	imes 2 	imes 1} = 120$.Since $4$ points are collinear,selecting these $4$ points will not form a triangle. The number of ways to select $3$ points from these $4$ collinear points is $^4C_3$.$^4C_3 = 4$.Therefore,the number of triangles that can be formed is $120 - 4 = 116$.

In a plane,there are $10$ points,out of which $4$ are collinear. The number of triangles that can be formed by joining these points is:

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