If three of the six vertices of a regular hex | vedclass

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Question

Only two equilateral triangle are possible $A_{1} A_{3} A_{5}$ and $A_{2} A_{5} A_{6}$

$\frac{2}{^{6} \mathrm{C}_{3}}=\frac{2}{20}=\frac{1}{10}$

Vedclass · Accepted Answer

$\frac{1}{{10}}$

Vedclass · Answer

Only two equilateral triangle are possible $A_{1} A_{3} A_{5}$ and $A_{2} A_{5} A_{6}$

$\frac{2}{^{6} \mathrm{C}_{3}}=\frac{2}{20}=\frac{1}{10}$

If three of the six vertices of a regular hexagon are chosen at random, then the probability that the triangle formed with these chosen vertices is equilateral is