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(D) $\rightarrow$ Increasing the intensity of incident light corresponds to an increase in the number of photons incident per unit area per unit time.

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increases the number of photons incident and the $K.E.$ of the ejected electrons remains unchanged

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(D) $ightarrow$ Increasing the intensity of incident light corresponds to an increase in the number of photons incident per unit area per unit time.$ightarrow$ The kinetic energy $(K.E.)$ of the ejected photoelectrons is determined by the Einstein photoelectric equation: $K.E._{max} = h
u - \phi$,where $h$ is Planck's constant,$
u$ is the frequency of incident light,and $\phi$ is the work function of the metal.$ightarrow$ Since the kinetic energy depends only on the frequency of the incident light and not on its intensity,increasing the intensity does not change the $K.E.$ of the ejected electrons.

In a photoelectric experiment,increasing the intensity of incident light :

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