Threshold wavelength for photoelectric emissi | vedclass

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Question

(B) The condition for photoelectric emission is that the wavelength of the incident radiation $(\lambda)$ must be less than or equal to the threshold

Vedclass · Accepted Answer

$50\,W$ $UV$ lamp

Vedclass · Answer

(B) The condition for photoelectric emission is that the wavelength of the incident radiation $(\lambda)$ must be less than or equal to the threshold wavelength $(\lambda_0)$.Given: $\lambda_0 = 5200\,\mathring{A}$.We know that the wavelength range for $UV$ (Ultraviolet) light is typically $100\,\mathring{A}$ to $4000\,\mathring{A}$,and the wavelength range for $IR$ (Infrared) light is greater than $7000\,\mathring{A}$.Since the wavelength of $UV$ light is less than $5200\,\mathring{A}$ and the wavelength of $IR$ light is greater than $5200\,\mathring{A}$,only the $UV$ lamp can cause photoelectric emission.Therefore,the correct option is the $50\,W$ $UV$ lamp.

Threshold wavelength for photoelectric emission from a metal surface is $5200\,\mathring{A}$. Photoelectrons will be emitted when this surface is illuminated with monochromatic radiation from:

Similar Questions

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