In a photoelectric effect experiment,f is the | vedclass

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(C) According to Einstein's photoelectric equation,$KE_{\max} = hf - \Phi$,where $\Phi$ is the work function.Statement $(A)$: Since $KE_{\max} = hf -

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$A, C$ and $D$

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(C) According to Einstein's photoelectric equation,$KE_{\max} = hf - \Phi$,where $\Phi$ is the work function.Statement $(A)$: Since $KE_{\max} = hf - \Phi$,if $f$ increases,$KE_{\max}$ increases. Thus,$(A)$ is correct.Statement $(B)$: Stopping potential $V_s$ depends only on the frequency of incident light and the work function of the metal. It is independent of the distance between the cathode and anode. Thus,$(B)$ is incorrect.Statement $(C)$: Stopping potential $V_s = \frac{KE_{\max}}{e} = \frac{hf - \Phi}{e}$. Since $V_s$ depends only on $f$ and $\Phi$,it remains constant if $I$ is increased. Saturation current is directly proportional to intensity $I$,so it increases. Thus,$(C)$ is correct.Statement $(D)$: Since $V_s = \frac{hf - \Phi}{e}$,if $\Phi$ is decreased,$V_s$ increases. Thus,$(D)$ is correct.Therefore,the correct statements are $(A), (C),$ and $(D)$.

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