(C) Total volume of the mixture = $75 \ L$.The ratio of milk to water is $2:1$.Amount of milk = $\frac{2}{2+1} \times 75 = \frac{2}{3} \times 75 = 50

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(C) Total volume of the mixture = $75 \ L$.The ratio of milk to water is $2:1$.Amount of milk = $\frac{2}{2+1} \times 75 = \frac{2}{3} \times 75 = 50 \ L$.Amount of water = $\frac{1}{2+1} \times 75 = \frac{1}{3} \times 75 = 25 \ L$.Let $x \ L$ of water be added to the mixture.The new amount of water becomes $(25+x) \ L$.The new ratio of milk to water is given as $1:2$.Therefore,$\frac{50}{25+x} = \frac{1}{2}$.Cross-multiplying,we get $50 \times 2 = 25+x$.$100 = 25+x$.$x = 100 - 25 = 75 \ L$.

Competitive Quantitative Aptitude Mixture and Alligation Mixture and Alligation

Medium

In a mixture of $75 \ L$,the ratio of milk to water is $2:1$. The amount of water to be further added to the mixture so as to make the ratio of the milk to water $1:2$ will be (in $L$):

A
$45$
B
$60$
C
$75$
D
$80$

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In a mixture of $75 \ L$,the ratio of milk to water is $2:1$. The amount of water to be further added to the mixture so as to make the ratio of the milk to water $1:2$ will be (in $L$):

Similar Questions

$8$ litres of water is added to $32$ litres of a solution containing $20 \%$ of alcohol in water. What is the approximate concentration of alcohol in the solution now? (in $\%$)

$A$ person has a chemical costing $Rs. 25$ per $litre$. In what ratio should water be mixed in the chemical so that by selling the mixture at $Rs. 20$ per $litre$,he may get a profit of $25\%$?

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In a mixture of $75 \, litres$,the ratio of milk to water is $2:1$. The amount of water to be further added to the mixture so as to make the ratio of milk to water $1:2$ will be (in $litres$):

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