In a metre bridge experiment,with a standard resistance in the right gap and a resistance coil dipped in water (in a beaker) in the left gap,the balancing length obtained is $l$. If the temperature of water is increased,the new balancing length is:

In a metre bridge experiment (see figure),the positions of the cell,$E$,and galvanometer,$G$,are interchanged. We shall observe in the galvanometer:

In a metre bridge experiment,the null point is obtained at $20 \,cm$ from the left end of the wire,when resistance $X$ is balanced against another resistance $Y$ $(X < Y)$. To balance a resistance $4X$ against $Y$,the new position of the null point from the same end will be: (in $\,cm$)

$A$ resistance wire connected in the left gap of a meter bridge balances a $10\, \Omega$ resistance in the right gap at a point which divides the bridge wire in the ratio $3: 2$. If the length of the resistance wire is $1.5\, m$,then the length of $1\, \Omega$ of the resistance wire is $....... \times 10^{-2}\, m$.

In a metre bridge experiment,the ratio of the left gap resistance to the right gap resistance is $2:3$. The balance point from the left is: (in $cm$)

Explain how the value of an unknown resistor can be obtained by using a meter bridge.