In a metre bridge experiment (see figure),the positions of the cell,$E$,and galvanometer,$G$,are interchanged. We shall observe in the galvanometer:

$n$ identical resistors are taken,in which $\frac{n}{2}$ resistors are joined in series in the left gap and the remaining $\frac{n}{2}$ resistors are joined in parallel in the right gap of a metre bridge. The balancing length in $cm$ is

In a meter bridge experiment,the balance point from the left is $37.5 \ cm$. The ratio of the right gap resistance to the left gap resistance is

The resistance of the meter bridge wire $AB$ in the given figure is $4\,\Omega$. With a cell of emf $\varepsilon_1 = 0.5\,\text{V}$ and rheostat resistance $R_{h1} = 2\,\Omega$,the null point is obtained at point $J$. When the cell is replaced by another one of emf $\varepsilon_2$,the same null point $J$ is found for $R_{h2} = 6\,\Omega$. The emf $\varepsilon_2$ is ................. $\text{V}$.

In the shown arrangement of the meter bridge experiment,if the length $AC$ corresponding to the null deflection of the galvanometer is $x$,what would be its value if the radius of the wire $AB$ is doubled?

When the two known resistances $R$ and $S$ are connected in the left and right gaps of a meter bridge respectively,the null point is found at a distance $l_1$ from the zero end of the meter bridge wire. An unknown resistance $X$ is now connected in parallel with $S$,and the null point is found at a distance $l_2$ from the zero end of the meter bridge wire. The unknown resistance $X$ is: