In a metre-bridge experiment,the balance point is obtained when the gaps are closed by $2 \Omega$ and $3 \Omega$ resistors. $A$ shunt of $x \Omega$ is added in parallel to the $3 \Omega$ resistor to shift the balance point by $22.5 \ cm$. The value of $x$ is: (in $Omega$)

$n$ identical resistors are taken,in which $\frac{n}{2}$ resistors are joined in series in the left gap and the remaining $\frac{n}{2}$ resistors are joined in parallel in the right gap of a metre bridge. The balancing length in $cm$ is

In a meter bridge,the resistances $R$ and $S$ are such that the null point is found at a distance of $40 \text{ cm}$ from one end. If a resistance of $10 \Omega$ is connected in parallel with shunt $S$,then the null point occurs at $90 \text{ cm}$ from the same end. The values of the two resistances $R$ and $S$ respectively are:

In a meter bridge experiment,the ratio of the left gap resistance to the right gap resistance is $2:3$. The balance length from the left end is (in $\,cm$)

In the experimental setup of a meter bridge shown in the figure,the null point is obtained at a distance of $40\,cm$ from $A$. If a $10\,\Omega$ resistor is connected in series with $R_1$,the null point shifts by $10\,cm$. The resistance that should be connected in parallel with $(R_1 + 10)\,\Omega$ such that the null point shifts back to its initial position is .............. $\Omega$.

In an experiment of a meter bridge, a null point is obtained at the centre of the bridge wire. When a resistance of $10\, \Omega$ is connected in one gap, the value of resistance in the other gap is ............. $\Omega$.