In a mercury thermometer, the ice point (lowe | vedclass

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(D) The relationship between any temperature scale and the Celsius scale is given by the formula: $\frac{X - 	ext{Lower Fixed Point}}{	ext{Upper Fix

Vedclass · Accepted Answer

$58$

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(D) The relationship between any temperature scale and the Celsius scale is given by the formula: $\frac{X - 	ext{Lower Fixed Point}}{	ext{Upper Fixed Point} - 	ext{Lower Fixed Point}} = \frac{C}{100}$.Here, the lower fixed point is $10^{\circ}$ and the upper fixed point is $130^{\circ}$.Substituting the given values: $\frac{X - 10}{130 - 10} = \frac{40}{100}$.$\frac{X - 10}{120} = \frac{40}{100}$.$X - 10 = \frac{40}{100} 	imes 120$.$X - 10 = 0.4 	imes 120 = 48$.$X = 48 + 10 = 58^{\circ}$.

In a mercury thermometer, the ice point (lower fixed point) is marked as $10^{\circ}$ and the steam point (upper fixed point) is marked as $130^{\circ}$. At $40^{\circ} C$ temperature, what will this thermometer read (in $^{\circ}$)?

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