(N/A) The relationship between the Celsius and Fahrenheit temperature scales can be derived from a linear graph of Fahrenheit temperature $(t_{F})$ versus Celsius temperature $(t_{C})$.
As shown in the graph,the freezing point of water is $0^{\circ}C$ or $32^{\circ}F$,and the boiling point of water is $100^{\circ}C$ or $212^{\circ}F$.
The equation for this straight line is given by:
$\frac{t_{F} - 32}{212 - 32} = \frac{t_{C} - 0}{100 - 0}$
Simplifying the denominators:
$\frac{t_{F} - 32}{180} = \frac{t_{C}}{100}$
Further simplifying the equation:
$t_{F} - 32 = \frac{180}{100} t_{C}$
$t_{F} - 32 = \frac{9}{5} t_{C}$
$t_{F} = \frac{9}{5} t_{C} + 32$