In a medical examination of students of a class,the following blood groups are recorded:
Blood group $A, AB, B, O$ Number of students $10, 13, 12, 5$
$A$ student is selected at random from the class. The probability that he/she has blood group $B$,is:
| Blood group | $A, AB, B, O$ |
| Number of students | $10, 13, 12, 5$ |
$A$ student is selected at random from the class. The probability that he/she has blood group $B$,is:
- A$\frac{1}{4}$
- B$\frac{13}{40}$
- C$\frac{1}{8}$
- D$\frac{3}{10}$
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$80$ bulbs are selected at random from a lot and their lifetime (in $hrs$) is recorded in the form of a frequency table given below:
Lifetime (in hours) $300$ $500$ $700$ $900$ $1100$ Frequency $10$ $12$ $23$ $25$ $10$
One bulb is selected at random from the lot. The probability that its lifetime is $1150$ hours is:
| Lifetime (in hours) | $300$ | $500$ | $700$ | $900$ | $1100$ |
| Frequency | $10$ | $12$ | $23$ | $25$ | $10$ |
One bulb is selected at random from the lot. The probability that its lifetime is $1150$ hours is:
Easy
View SolutionTwo coins are tossed $1000$ times and the outcomes are recorded as below:
Number of heads $2$ $1$ $0$ Frequency $200$ $550$ $250$
Based on this information,the probability for at most one head is
| Number of heads | $2$ | $1$ | $0$ |
| Frequency | $200$ | $550$ | $250$ |
Based on this information,the probability for at most one head is
Medium
View Solution$80$ bulbs are selected at random from a lot and their lifetime (in $hrs$) is recorded in the form of a frequency table given below:
Lifetime (in hours) $300$ $500$ $700$ $900$ $1100$ Frequency $10$ $12$ $23$ $25$ $10$
The probability that a bulb selected randomly from the lot has a lifetime less than $900$ hours is:
| Lifetime (in hours) | $300$ | $500$ | $700$ | $900$ | $1100$ |
| Frequency | $10$ | $12$ | $23$ | $25$ | $10$ |
The probability that a bulb selected randomly from the lot has a lifetime less than $900$ hours is:
Medium
View SolutionThe probability of an impossible event is ........
Easy
View SolutionHere is an extract from a mortality table.
Age (in years) Number of persons surviving out of a sample of one million $60$ $16090$ $61$ $11490$ $62$ $8012$ $63$ $5448$ $64$ $3607$ $65$ $2320$
What is the probability that a person aged $61$ will live for $4$ years?
| Age (in years) | Number of persons surviving out of a sample of one million |
| $60$ | $16090$ |
| $61$ | $11490$ |
| $62$ | $8012$ |
| $63$ | $5448$ |
| $64$ | $3607$ |
| $65$ | $2320$ |
What is the probability that a person aged $61$ will live for $4$ years?
Medium
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