In a given series $LCR$ circuit,$R = 4\,\Omega ,$ $X_L = 5\,\Omega $ and $X_C = 8\, \Omega ,$ the current:

$A$ series $LCR$ circuit has $R=200 \Omega$, $L=663 \text{ mH}$, and $C=26.5 \mu F$. The applied alternating voltage has an amplitude of $50 \text{ V}$ and a frequency of $60 \text{ Hz}$ such that $X_{L}=250 \Omega$ and $X_{C}=100 \Omega$. The peak current is: (in $\text{ A}$)

In the circuit shown in the figure,what will be the reading of the voltmeter (in $, V$)?

In the circuit diagram shown,$X_C = 100 \, \Omega$,$X_L = 200 \, \Omega$,and $R = 100 \, \Omega$. The source voltage is $V = 200 \sin(\omega t) \, \text{V}$. The effective $(RMS)$ current through the source is:

Two coils require $20 \ min$ and $60 \ min$ respectively to produce the same amount of heat energy when connected separately to the same source. If they are connected in parallel to the same source,the time required to produce the same amount of heat by the combination of coils will be . . . . . . $min$.

$A$ series $LR$ circuit is connected to an ac source of frequency $\omega$ and the inductive reactance is equal to $2R$. $A$ capacitance of capacitive reactance equal to $R$ is added in series with $L$ and $R$. The ratio of the new power factor to the old one is