(B) In Young's double-slit interference experiment, the fringe width $\beta$ is given by the formula:$\beta = \frac{\lambda D}{d}$where $\lambda$ is t

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(B) In Young's double-slit interference experiment, the fringe width $\beta$ is given by the formula:$\beta = \frac{\lambda D}{d}$where $\lambda$ is the wavelength, $D$ is the distance between the slits and the screen, and $d$ is the separation between the slits.Given:$\beta_1 = 1.2 \ \text{mm}$$d_2 = 1.5 \times d_1$Since $\beta \propto \frac{1}{d}$ (assuming $\lambda$ and $D$ remain constant),$\frac{\beta_1}{\beta_2} = \frac{d_2}{d_1} = 1.5$Substituting the values:$\frac{1.2}{\beta_2} = 1.5$$\beta_2 = \frac{1.2}{1.5} = 0.8 \ \text{mm}$Thus, the new fringe width is $0.8 \ \text{mm}$.

Class 12 Physics Wave Optics Young's Double Slit Experiment (YDSE)

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In a double-slit interference experiment, the fringe width obtained with light of wavelength $5900 \ \mathring{A}$ was $1.2 \ \text{mm}$ for parallel narrow slits placed $2 \ \text{mm}$ apart. In this arrangement, if the slit separation is increased by one-and-a-half times the previous value, then the fringe width is: (in $\text{mm}$)

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A
$0.9$
B
$0.8$
C
$1.8$
D
$1.6$

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In a Young's double slit experiment,the wavelength of red light is $7.8 \times 10^{-5} \,cm$ and that of blue light is $5.2 \times 10^{-5} \,cm$. The value of $n$ for which $(n+1)^{\text{th}}$ blue bright band coincides with $n^{\text{th}}$ bright red band is ..........

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If the monochromatic source in Young's double slit experiment is replaced by white light,then

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In Young's double-slit experiment,we get $10$ fringes in the field of view using monochromatic light of wavelength $4000 \text{ } \mathring{A}$. If we use monochromatic light of wavelength $5000 \text{ } \mathring{A}$,then the number of fringes obtained in the same field of view is

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In Young's double slit experiment,how many maximas can be obtained on a screen (including the central maximum) on both sides of the central fringe if $\lambda = 2000\,{\mathring A}$ and $d = 7000\,{\mathring A}$?

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$A$ beam of electrons is used in $Y.D.S.E.$ The slit width is $d$. When the velocity of the electrons is increased,then:

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In a Young's double slit experiment,the wavelength of red light is $7.8 \times 10^{-5} \,cm$ and that of blue light is $5.2 \times 10^{-5} \,cm$. The value of $n$ for which $(n+1)^{\text{th}}$ blue bright band coincides with $n^{\text{th}}$ bright red band is ..........

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In Young's double-slit experiment,we get $10$ fringes in the field of view using monochromatic light of wavelength $4000 \text{ } \mathring{A}$. If we use monochromatic light of wavelength $5000 \text{ } \mathring{A}$,then the number of fringes obtained in the same field of view is

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