If the monochromatic source in Young's double | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) In Young's double slit experiment,the path difference at the central point on the screen is zero for all wavelengths present in white light.Since

Vedclass · Accepted Answer

There will be a central bright white fringe surrounded by a few coloured fringes

Vedclass · Answer

(B) In Young's double slit experiment,the path difference at the central point on the screen is zero for all wavelengths present in white light.Since the condition for constructive interference is $\Delta x = n\lambda$,for $n=0$,the path difference is zero regardless of the wavelength $\lambda$.Therefore,all colors overlap at the central point,resulting in a central bright white fringe.For other fringes,the fringe width is given by $\beta = \frac{\lambda D}{d}$. Since $\beta$ depends on the wavelength $\lambda$,different colors will form fringes at different positions,resulting in a few coloured fringes surrounding the central white fringe.

If the monochromatic source in Young's double slit experiment is replaced by white light,then

Similar Questions

In a Young's double-slit experiment, interference fringes are obtained on a screen at a distance of $1 \, m$ using light of wavelength $6000 \, \mathring{A}$. The distance between the slits is $1 \, mm$. The fringe width is:

In a double slit experiment,at a certain point on the screen,the path difference between the two interfering waves is $\frac{1}{8}$ of a wavelength. The ratio of the intensity of light at that point to that at the centre of a bright fringe is:

In Young's double slit experiment,the intensity at a point is $1/4$ of the maximum intensity. The angular position of this point is:

In Young's double-slit experiment,when two light waves form the third minimum,they have:

Vedclass Test Series

Exam Paper Generator

Online Exam Module