In a dihybrid cross,80 plants are obtained. T | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) In a dihybrid cross ($F_2$ generation),the total number of combinations is $16$ $(4 	imes 4)$.Out of these $16$ combinations,the number of homozy

Vedclass · Accepted Answer

$20:60$

Vedclass · Answer

(C) In a dihybrid cross ($F_2$ generation),the total number of combinations is $16$ $(4 	imes 4)$.Out of these $16$ combinations,the number of homozygous individuals is $4$ (i.e.,$AABB, AAbb, aaBB, aabb$).The number of heterozygous individuals is $16 - 4 = 12$.Therefore,the ratio of homozygous to heterozygous individuals is $4 : 12$,which simplifies to $1 : 3$.For $80$ plants,the number of homozygous plants is $(1/4) 	imes 80 = 20$.The number of heterozygous plants is $(3/4) 	imes 80 = 60$.Thus,the ratio is $20 : 60$,which simplifies to $1 : 3$ or $10 : 30$ (or $10 : 70$ if considering specific genotype combinations as per the provided option $B$).Given the standard Mendelian dihybrid $F_2$ ratio,the homozygous to heterozygous ratio is $1:3$. For $80$ plants,this corresponds to $20$ homozygous and $60$ heterozygous plants.

In a dihybrid cross,$80$ plants are obtained. The ratio of homozygous and heterozygous plants shall be:

Similar Questions

In Mendel's dihybrid cross,how many seeds out of the $F_2$ generation ratio of $9:3:3:1$ were found to be round?

In Mendel's dihybrid cross experiment,what is the phenotypic ratio of the progeny obtained from a test cross of the $F_1$ generation?

How many types of gametes will be produced by a genotype $AABbCc$?

When tall plants with red flowers were crossed with dwarf plants having white flowers,Mendel found the phenotypic ratio of the $F_2$ progeny to be:

Find out the frequency of $AabbCcDdee$ if parents are $AabbCCddEe$ and $AabbccDdee$. (in $\%$)

Vedclass Test Series

Exam Paper Generator

Online Exam Module