In a crystalline compound,A atoms occupy all | vedclass

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(C) $1$. Number of $A$ atoms at corners = $8 	imes \frac{1}{8} = 1$. $2$. Number of $B$ atoms at face centers = $6 	imes \frac{1}{2} = 3$. $3$. Numb

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$AB_3C_3D_8$

Vedclass · Answer

(C) $1$. Number of $A$ atoms at corners = $8 	imes \frac{1}{8} = 1$. $2$. Number of $B$ atoms at face centers = $6 	imes \frac{1}{2} = 3$. $3$. Number of $C$ atoms at edge centers = $12 	imes \frac{1}{4} = 3$. $4$. Total number of atoms of $A$ and $B$ is $1 + 3 = 4$. The number of tetrahedral voids formed by $4$ atoms is $2 	imes 4 = 8$. Thus,$D = 8$. $5$. The ratio $A:B:C:D$ is $1:3:3:8$. $6$. The formula is $AB_3C_3D_8$.

In a crystalline compound,$A$ atoms occupy all corners,$B$ atoms occupy all face-centered positions,$C$ atoms occupy all edge centers,and $D$ atoms occupy all tetrahedral voids formed by $A$ and $B$ atoms. Find the formula of the compound.

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