In a compound,C, H, and N atoms are present i | vedclass

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(C) The total ratio sum is $9 + 1 + 3.5 = 13.5$.Calculate the moles of each element in $108 \ g$ of the compound:Moles of $C = \frac{(9 / 13.5) 	imes

Vedclass · Accepted Answer

$C_6H_8N_2$

Vedclass · Answer

(C) The total ratio sum is $9 + 1 + 3.5 = 13.5$.Calculate the moles of each element in $108 \ g$ of the compound:Moles of $C = \frac{(9 / 13.5) 	imes 108}{12} = \frac{0.6667 	imes 108}{12} = 6 \ mol$.Moles of $H = \frac{(1 / 13.5) 	imes 108}{1} = \frac{0.0741 	imes 108}{1} = 8 \ mol$.Moles of $N = \frac{(3.5 / 13.5) 	imes 108}{14} = \frac{0.2593 	imes 108}{14} = 2 \ mol$.Thus,the molecular formula is $C_6H_8N_2$.

In a compound,$C, H,$ and $N$ atoms are present in the ratio $9 : 1 : 3.5$ by weight. If the molecular weight of the compound is $108$,what is its molecular formula?

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