In a common emitter transistor amplifier,the output voltage and input voltage have a phase difference of

$A$ transistor is connected in common emitter circuit configuration. The collector supply voltage is $10 \, V$ and the voltage drop across a resistor of $1000 \, \Omega$ in the collector circuit is $0.6 \, V$. If the current gain factor $(\beta)$ is $24$,then the base current is $.... \, \mu A$. (Round off to the Nearest Integer)

In a $CE$ transistor amplifier,there is a current and voltage gain associated with the circuit. In other words,there is a power gain. Considering power as a measure of energy,does the circuit violate the law of conservation of energy?

In an $n-p-n$ common emitter $(CE)$ transistor,the collector current changes from $5\,mA$ to $16\,mA$ for a change in base current from $100\,\mu A$ to $200\,\mu A$,respectively. The current gain of the transistor is:

For a transistor,$\frac{1}{\alpha_{DC}} - \frac{1}{\beta_{DC}}$ is equal to [where $\alpha_{DC}$ and $\beta_{DC}$ are current amplification factors].

The output characteristics of a transistor are shown in the figure. When $V_{CE} = 10\, V$ and $I_{C} = 4.0\, mA$,then the value of $\beta_{ac}$ is: