In an $n-p-n$ common emitter $(CE)$ transistor,the collector current changes from $5\,mA$ to $16\,mA$ for a change in base current from $100\,\mu A$ to $200\,\mu A$,respectively. The current gain of the transistor is:

In the study of a transistor as an amplifier,if $\alpha = \frac{I_C}{I_E} = 0.98$ and $\beta = \frac{I_C}{I_B} = 49$,where $I_C, I_B,$ and $I_E$ are collector,base,and emitter currents respectively,then $\left(\frac{1}{\alpha} - \frac{1}{\beta}\right)$ is equal to:

In a common base amplifier circuit,calculate the change in base current if the change in emitter current is $2\, mA$ and $\alpha = 0.98$.

In a common base mode of a transistor,the collector current is $5.488 \ mA$ for an emitter current of $5.60 \ mA$. The value of the base current amplification factor $(\beta)$ will be

In the study of a transistor as an amplifier,the ratio of collector current to emitter current is $0.98$. Then,the ratio of collector current to base current will be:

In a common emitter transistor circuit,the base current is $40 \ \mu A$. Find the value of $V_{BE}$. (in $V$)