In a common emitter transistor amplifier,the load resistance is $6.5 \text{ k}\Omega$ and the input resistance is $1.3 \text{ k}\Omega$. If the current gain is $78$,the voltage gain is:

An $n-p-n$ transistor is connected in common-emitter configuration as shown in the figure. If the collector current is $5 \text{ mA}$,$V_{BE} = 0.6 \text{ V}$,$V_{CE} = 3 \text{ V}$,and the common-emitter current amplification factor $\beta = 50$,then the values of $R_1$ and $R_2$ are respectively.

In the given circuit,a transistor with a current gain $\beta = 100$ is used. To have $V_{CE} = 5 \text{ V}$ and $V_{BE} = 0$,what should be the value of the base resistance $R_b$?

For a common base transistor,the current gain is $\alpha = 0.98$. To produce a change of $2 \ mA$ in the emitter current,the change in the base current must be ......... $mA$.

An $N-P-N$ transistor conducts when:

For a transistor,in a common emitter arrangement,the alternating current gain $\beta$ is given by