In a common emitter transistor amplifier, an | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) Given: Input signal voltage change $\Delta V_{in} = 10 \ mV = 10 	imes 10^{-3} \ V$.Change in base current $\Delta I_{B} = 50 \ \mu A = 50 	imes

Vedclass · Accepted Answer

$25$

Vedclass · Answer

(C) Given: Input signal voltage change $\Delta V_{in} = 10 \ mV = 10 	imes 10^{-3} \ V$.Change in base current $\Delta I_{B} = 50 \ \mu A = 50 	imes 10^{-6} \ A$.Change in collector current $\Delta I_{C} = 5 \ mA = 5 	imes 10^{-3} \ A$.Load resistance $R_{L} = 5 \ k\Omega = 5 	imes 10^{3} \ \Omega$.The change in output voltage $\Delta V_{out}$ is given by the product of the change in collector current and the load resistance:$\Delta V_{out} = \Delta I_{C} 	imes R_{L}$Substituting the values:$\Delta V_{out} = (5 	imes 10^{-3} \ A) 	imes (5 	imes 10^{3} \ \Omega)$$\Delta V_{out} = 25 \ V$.Thus, the change in output voltage is $25 \ V$.

Similar Questions

In an $NPN$ transistor,$10^{10}$ electrons enter the emitter in $10^{-6} \ s$ and $2 \%$ of electrons recombine with holes in the base. The current ratios $\alpha$ and $\beta$ of the transistor are respectively (nearly):

In an $n-p-n$ transistor circuit,the collector current is $20 \, mA$. If $90 \%$ of the emitted electrons reach the collector,calculate the emitter current and base current.

In a $p-n-p$ transistor working as a common base amplifier, when the current gain is $0.96$ and emitter current is $7.2 \,mA$, the base current is (in $\,mA$)

For a transistor,the current ratio $\beta_{dc}$ is defined as the ratio of:

$A$ change of $8.0 \,mA$ in the emitter current brings a change of $7.9 \,mA$ in the collector current. The values of $\alpha$ and $\beta$ are

Vedclass Test Series

Exam Paper Generator

Online Exam Module