In a $p-n-p$ transistor working as a common base amplifier, when the current gain is $0.96$ and emitter current is $7.2 \,mA$, the base current is (in $\,mA$)

For a common emitter amplifier,the current gain is $50$. If the emitter current is $6.6 \ mA$,then the value of the base current is ........ (in $mA$)

In an $n-p-n$ transistor,$10^{8}$ electrons enter the emitter in $10^{-8} \,s$. If $1\%$ of electrons are lost in the base,the fraction of current that enters the collector and the current amplification factor $\beta$ are respectively:

The input resistance of a common emitter transistor amplifier,if the output resistance is $500\,k\Omega$,the current gain $\alpha = 0.98$ and power gain is $6.0625 \times 10^6$,is.......$\Omega$.

In the following common emitter circuit, if $\beta=100$, $V_{CE}=7 \, V$, $V_{BE}$ is negligible, and $R_C=2 \, k\Omega$, then $I_B=$ (in $\, mA$)?

An oscillator is nothing but an amplifier with