In a common emitter amplifier,a.c. current ga | vedclass

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(D) For a common emitter $(CE)$ amplifier,the voltage gain $(A_v)$ is defined as the product of the current gain $(\beta)$ and the ratio of the output

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$200$

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(D) For a common emitter $(CE)$ amplifier,the voltage gain $(A_v)$ is defined as the product of the current gain $(\beta)$ and the ratio of the output load resistance $(R_o)$ to the input resistance $(R_i)$.Given:$\beta = 40$$R_i = 2 \ k\Omega$$R_o = 10 \ k\Omega$Using the formula:$A_v = \beta 	imes \left( \frac{R_o}{R_i} ight)$$A_v = 40 	imes \left( \frac{10 \ k\Omega}{2 \ k\Omega} ight)$$A_v = 40 	imes 5$$A_v = 200$

In a common emitter amplifier,a.c. current gain is $40$ and input resistance is $2 \ k\Omega$. The load resistance is given as $10 \ k\Omega$. Then the voltage gain is

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