In a college,25% of the boys and 10% of the g | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) Let the total number of students in the college be $100$.Since girls constitute $60\%$ of the total students,the number of girls $= 60$ and the nu

Vedclass · Accepted Answer

$\frac{3}{8}$

Vedclass · Answer

(B) Let the total number of students in the college be $100$.Since girls constitute $60\%$ of the total students,the number of girls $= 60$ and the number of boys $= 100 - 60 = 40$.Number of boys studying Mathematics $= 25\% 	ext{ of } 40 = \frac{25}{100} 	imes 40 = 10$.Number of girls studying Mathematics $= 10\% 	ext{ of } 60 = \frac{10}{100} 	imes 60 = 6$.Total number of students studying Mathematics $= 10 + 6 = 16$.We need to find the probability that the student is a girl,given that the student studies Mathematics.Using the conditional probability formula,$P(	ext{Girl} | 	ext{Maths}) = \frac{	ext{Number of girls studying Maths}}{	ext{Total number of students studying Maths}}$.$P(	ext{Girl} | 	ext{Maths}) = \frac{6}{16} = \frac{3}{8}$.

In a college,$25\%$ of the boys and $10\%$ of the girls offer Mathematics. The girls constitute $60\%$ of the total number of students. If a student is selected at random and is found to be studying Mathematics,the probability that the student is a girl,is

Similar Questions

$A$ bag contains $3$ black and $4$ white balls. Two balls are drawn one by one at random without replacement. The probability that the second drawn ball is white,is

$A$ bag contains $4$ white balls and $2$ black balls. Another bag contains $3$ white balls and $5$ black balls. If one ball is drawn from each bag,then the probability that both the balls are black,is

$A$ box contains $6$ nails and $10$ nuts. Half of the nails and half of the nuts are rusted. If one item is chosen at random,what is the probability that it is rusted or is a nail?

$A$ card is drawn from a pack of $52$ cards. If $A =$ card is of diamond,$B =$ card is an ace and $A \cap B =$ card is the ace of diamond,then events $A$ and $B$ are

What is the chance that a leap year,selected at random,will contain $53$ Sundays (in $/7$)?

Vedclass Test Series

Exam Paper Generator

Online Exam Module