In a coil of resistance 100 Omega,a current | vedclass

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(C) According to Faraday's law of electromagnetic induction,the induced electromotive force $(EMF)$ is given by $\varepsilon = \frac{d\phi}{dt}$.Also,

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$250$

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(C) According to Faraday's law of electromagnetic induction,the induced electromotive force $(EMF)$ is given by $\varepsilon = \frac{d\phi}{dt}$.Also,by Ohm's law,$\varepsilon = iR$,where $i$ is the induced current and $R$ is the resistance of the coil.Equating the two expressions,we get $iR = \frac{d\phi}{dt}$,which implies $d\phi = R \cdot i \cdot dt$.Integrating both sides,the total change in magnetic flux $\Delta\phi$ is given by $\Delta\phi = R \int i \, dt$.The integral $\int i \, dt$ represents the area under the current-time graph.From the given graph,the area is a right-angled triangle with base $= 0.5 \, s$ and height $= 10 \, A$.Area $= \frac{1}{2} 	imes 	ext{base} 	imes 	ext{height} = \frac{1}{2} 	imes 0.5 	imes 10 = 2.5 \, C$.Therefore,the magnitude of change in flux is $\Delta\phi = R 	imes 	ext{Area} = 100 \, \Omega 	imes 2.5 \, C = 250 \, Wb$.

In a coil of resistance $100 \ \Omega$,a current is induced by changing the magnetic flux through it as shown in the figure. The magnitude of change in flux through the coil is......$Wb$.

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