(C) The formula for the area of a minor sector is given by: $\text{Area} = \frac{\pi r^{2} \theta}{360^{\circ}}$.Given radius $r = 42\,cm$ and central

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(C) The formula for the area of a minor sector is given by: $\text{Area} = \frac{\pi r^{2} \theta}{360^{\circ}}$.Given radius $r = 42\,cm$ and central angle $\theta = 120^{\circ}$.Substituting the values: $\text{Area} = \frac{22}{7} \times 42 \times 42 \times \frac{120^{\circ}}{360^{\circ}}$.Simplifying the expression: $\text{Area} = \frac{22}{7} \times 42 \times 42 \times \frac{1}{3}$.$\text{Area} = 22 \times 6 \times 14 = 1848\,cm^{2}$.

Class 10 Mathematics Areas Related to Circles Mix Examples - Areas Related to Circles

Easy

In a circle with radius $42\,cm$,an arc subtends an angle of measure $120^{\circ}$ at the centre. Then,the area of the minor sector formed by that arc is $\ldots \ldots \ldots \,cm^{2}$.

A
$924$
B
$44$
C
$1848$
D
$1760$

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Mix Examples - Areas Related to Circles

$\widehat{ACB}$ is a minor arc of $\odot(O, 8 \, cm)$. If $m\angle AOB = 45^\circ$, the length of minor $\widehat{ACB}$ is $\dots \, cm$. (in $\pi$)

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In a circle with radius $6.3\, cm$,a minor arc subtends an angle of measure $40^{\circ}$ at the centre. The area of the minor sector corresponding to that arc is $\ldots \ldots cm^{2}$.

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$A$ chord of a circle of radius $20\, cm$ subtends an angle of $90^{\circ}$ at the centre. Find the area of the corresponding major segment of the circle. (Use $\pi=3.14$) (in $cm^2$)

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The radius of a wheel of a car is $21 \, cm$. If it makes $800$ rotations per minute,find the speed of the car in $km/h$.

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Find the difference of the areas of a sector of angle $120^{\circ}$ and its corresponding major sector of a circle of radius $21 \, cm$. (in $cm^2$)

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In a circle with radius $42\,cm$,an arc subtends an angle of measure $120^{\circ}$ at the centre. Then,the area of the minor sector formed by that arc is $\ldots \ldots \ldots \,cm^{2}$.

Similar Questions

$\widehat{ACB}$ is a minor arc of $\odot(O, 8 \, cm)$. If $m\angle AOB = 45^\circ$, the length of minor $\widehat{ACB}$ is $\dots \, cm$. (in $\pi$)

In a circle with radius $6.3\, cm$,a minor arc subtends an angle of measure $40^{\circ}$ at the centre. The area of the minor sector corresponding to that arc is $\ldots \ldots cm^{2}$.

$A$ chord of a circle of radius $20\, cm$ subtends an angle of $90^{\circ}$ at the centre. Find the area of the corresponding major segment of the circle. (Use $\pi=3.14$) (in $cm^2$)

The radius of a wheel of a car is $21 \, cm$. If it makes $800$ rotations per minute,find the speed of the car in $km/h$.

Find the difference of the areas of a sector of angle $120^{\circ}$ and its corresponding major sector of a circle of radius $21 \, cm$. (in $cm^2$)

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