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(D) The area of a sector of a circle is given by the formula: $	ext{Area} = \frac{	heta}{360^\circ} 	imes \pi r^2$. Since the two radii are perpend

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$7$

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(D) The area of a sector of a circle is given by the formula: $	ext{Area} = \frac{	heta}{360^\circ} 	imes \pi r^2$. Since the two radii are perpendicular to each other,the central angle $	heta = 90^\circ$. Given,$	ext{Area} = 38.5 \, cm^2$ and $\pi = \frac{22}{7}$. Substituting the values: $38.5 = \frac{90^\circ}{360^\circ} 	imes \frac{22}{7} 	imes r^2$. $38.5 = \frac{1}{4} 	imes \frac{22}{7} 	imes r^2$. $38.5 = \frac{11}{14} 	imes r^2$. $r^2 = \frac{38.5 	imes 14}{11}$. $r^2 = 3.5 	imes 14 = 49$. $r = \sqrt{49} = 7 \, cm$.

In a circle,the area of a sector formed by two radii perpendicular to each other is $38.5 \, cm^2$. Find the radius of the circle (in $cm$).

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