In a box,there are $8$ red,$7$ blue,and $6$ green balls. One ball is picked up at random. What is the probability that it is neither red nor green?

  • A
    $\frac{1}{3}$
  • B
    $\frac{3}{4}$
  • C
    $\frac{7}{19}$
  • D
    $\frac{8}{21}$

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