A word consists of 11 letters in which there | vedclass

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(B) Total number of letters = $11$.Number of consonants = $7$.Number of vowels = $4$.We need to choose $2$ letters out of $11$. The total number of wa

Vedclass · Accepted Answer

$\frac{21}{55}$

Vedclass · Answer

(B) Total number of letters = $11$.Number of consonants = $7$.Number of vowels = $4$.We need to choose $2$ letters out of $11$. The total number of ways to choose $2$ letters is given by $^{11}C_2 = \frac{11 	imes 10}{2 	imes 1} = 55$.The number of ways to choose $2$ consonants out of $7$ is given by $^7C_2 = \frac{7 	imes 6}{2 	imes 1} = 21$.The probability that both chosen letters are consonants is the ratio of the number of favorable outcomes to the total number of outcomes.Required probability = $\frac{^7C_2}{^{11}C_2} = \frac{21}{55}$.

$A$ word consists of $11$ letters in which there are $7$ consonants and $4$ vowels. If $2$ letters are chosen at random,then the probability that both of them are consonants is:

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