In a biprism experiment,the distance between | vedclass

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(B) The fringe width $\beta$ is given by the formula $\beta = \frac{\lambda D}{d}$,where $\lambda$ is the wavelength of light,$D$ is the distance betw

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unchanged.

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(B) The fringe width $\beta$ is given by the formula $\beta = \frac{\lambda D}{d}$,where $\lambda$ is the wavelength of light,$D$ is the distance between the slit and the eyepiece,and $d$ is the distance between the two coherent sources.Initially,$\beta = \frac{\lambda D}{d}$.In the new situation,the distance between the sources becomes $d' = 2d$ and the distance between the slit and the eyepiece becomes $D' = 2D$.The new fringe width $\beta'$ is given by $\beta' = \frac{\lambda D'}{d'} = \frac{\lambda (2D)}{(2d)} = \frac{\lambda D}{d}$.Therefore,$\beta' = \beta$,which means the fringe width remains unchanged.

In a biprism experiment,the distance between the two sources is doubled and the distance between the slit and the eyepiece is also doubled. Then the width of the fringe is

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