In a balanced meter bridge,the segment of wire opposite to a known resistance of $70 \Omega$ is $70 \text{ cm}$. The unknown resistance is (in $Omega$)

  • A
    $30$
  • B
    $60$
  • C
    $90$
  • D
    $15$

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Similar Questions

Resistances in the left gap and right gap of a meter bridge are $10 \Omega$ and $30 \Omega$ respectively. If the resistances in the two gaps are interchanged, the balance point will shift to the right by: (in $\text{cm}$)

$A$ student obtained the following observations in an experiment of a meter bridge to find the unknown resistance of the circuit. The most accurate value of the unknown resistance is ............ $\Omega$.
$S.No.$$R$$l$$100-l$$S = \left( \frac{100-l}{l} \right)R$
$1$$20\,\Omega$$43$$57$$26.51\,\Omega$
$2$$30\,\Omega$$51$$49$$28.82\,\Omega$
$3$$40\,\Omega$$59$$41$$27.80\,\Omega$
$4$$60\,\Omega$$70$$30$$25.71\,\Omega$

In a meter bridge,the gaps are enclosed by resistances of $2 \ \Omega$ and $3 \ \Omega$. The value of shunt to be added to the $3 \ \Omega$ resistor to shift the balancing point by $22.5 \ cm$ is (in $Omega$)

In a metre bridge experiment,the ratio of the left gap resistance to the right gap resistance is $2:3$. The balance point from the left is: (in $cm$)

The experimental setup of a meter bridge is shown in the figure. If the null deflection point of the galvanometer is at distance $x$ from end $A$,what will be the new null point if the radius of the wire $AB$ is doubled?

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