In a U-tube as shown in the figure,water and | vedclass

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(B) At the same horizontal level in a continuous static fluid,the pressure is the same. Let the pressure at the bottom of the $U$-tube be $P$. The pre

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$750$

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(B) At the same horizontal level in a continuous static fluid,the pressure is the same. Let the pressure at the bottom of the $U$-tube be $P$. The pressure exerted by the water column on the left side is $P_{	ext{left}} = P_0 + ho_{	ext{water}} g h_{	ext{water}}$,where $P_0$ is atmospheric pressure. The pressure exerted by the oil column on the right side is $P_{	ext{right}} = P_0 + ho_{	ext{oil}} g h_{	ext{oil}}$. Since the pressures at the bottom are equal,we have: $ho_{	ext{water}} g h_{	ext{water}} = ho_{	ext{oil}} g h_{	ext{oil}}$ $ho_{	ext{oil}} = \frac{ho_{	ext{water}} h_{	ext{water}}}{h_{	ext{oil}}}$ Given $ho_{	ext{water}} = 1000 \; kg/m^3$,$h_{	ext{water}} = 15 \; cm$,and $h_{	ext{oil}} = 20 \; cm$: $ho_{	ext{oil}} = \frac{1000 	imes 15}{20} = 750 \; kg/m^3$.

In a $U$-tube as shown in the figure,water and oil are in the left and right sides of the tube,respectively. The heights from the bottom for the water and oil columns are $15 \; cm$ and $20 \; cm$,respectively. The density of the oil is ...... $kg/m^3$. [Take $\rho_{\text{water}} = 1000 \; kg/m^3$]

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