In mRNA,AUG is the initiation codon and UAA,U | vedclass

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(D) The process of translation begins at the initiation codon $(AUG)$ and terminates at a stop codon ($UAA$,$UAG$,or $UGA$).For an $mRNA$ to be transl

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$AUG \ UAU \ UUC \ UGC \ CUC \ UAG$

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(D) The process of translation begins at the initiation codon $(AUG)$ and terminates at a stop codon ($UAA$,$UAG$,or $UGA$).For an $mRNA$ to be translated completely,the initiation codon must be present at the start,and the termination codon must be present at the very end of the sequence.In option $(d)$,the sequence is $AUG \ UAU \ UUC \ UGC \ CUC \ UAG$. Here,$AUG$ acts as the initiation codon,and $UAG$ acts as the termination codon at the end of the sequence,allowing the entire segment to be translated.

Genetic Code	Amino Acid	Anticodon
$a$	$Met$	$b$
$GGA$	$c$	$d$
$UUA$	$e$	$f$
$g$	$h$	$ACA$

In $mRNA$,$AUG$ is the initiation codon and $UAA$,$UAG$,and $UGA$ are termination codons; therefore,a polypeptide cannot be synthesized beyond any of these triplets to the end of the $mRNA$. Which one of the following $mRNA$ sequences can be translated completely?

Similar Questions

Complete the following table regarding the genetic code,amino acids,and anticodons:
Genetic Code Amino Acid Anticodon
$a$ $Met$ $b$
$GGA$ $c$ $d$
$UUA$ $e$ $f$
$g$ $h$ $ACA$

What is indicated by $AUG$?

There is only one possible sequence of amino acids when deduced from a given nucleotide sequence. However,multiple nucleotide sequences can be deduced from a single amino acid sequence. Explain this phenomenon.

Which of the following triplet codons correctly represents a start or stop signal for protein synthesis?

Find out the incorrect match.

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