Class 11MathematicsTrigonometrical EquationsRelation between sides and angles, Solutions of triangles
Easy$\Delta ABC$ में,$(a-b)^2 \cos^2 \frac{C}{2} + (a+b)^2 \sin^2 \frac{C}{2} =$
- A$b^2$
- B$c^2$
- C$a^2$
- D$a^2+b^2+c^2$
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Similar Questions
किसी त्रिभुज $ABC$ में,$(a + b)^2 \sin^2 \frac{C}{2} + (a - b)^2 \cos^2 \frac{C}{2} =$
त्रिभुज $ABC$ में,यदि $\frac{r}{r_1} = \frac{1}{2}$ है,तो $4 \tan \frac{A}{2} \left( \tan \frac{B}{2} + \tan \frac{C}{2} \right) = $
DifficultTS EAMCET 2022
View Solution$\triangle ABC$ में,यदि $\frac{\cos A}{a} = \frac{\cos B}{b} = \frac{\cos C}{c}$ है,तो $\triangle ABC$ है
यदि $\Delta ABC$ में $A = 60^\circ$,$a = 5$,और $b = 4\sqrt{3}$ है,तो $B =$
Easy
View Solution$\Delta ABC$ में,व्यंजक $\frac{\cos C + \cos A}{c + a} + \frac{\cos B}{b}$ का मान किसके बराबर है?
Easy
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