In Delta ABC,AB = 6 text{ cm} and BC = 9 text | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) According to the triangle inequality theorem,the sum of the lengths of any two sides of a triangle must be greater than the length of the third si

Vedclass · Accepted Answer

$15$

Vedclass · Answer

(A) According to the triangle inequality theorem,the sum of the lengths of any two sides of a triangle must be greater than the length of the third side.In $\Delta ABC$,the sum of sides $AB$ and $BC$ must be greater than $AC$.Therefore,$AB + BC > AC$.Substituting the given values: $6 	ext{ cm} + 9 	ext{ cm} > AC$.$15 	ext{ cm} > AC$,which means $AC Thus,the length of side $AC$ must be less than $15 	ext{ cm}$.

In $\Delta ABC$,$AB = 6 \text{ cm}$ and $BC = 9 \text{ cm}$,then $AC < \dots \text{ cm}$.

Similar Questions

Prove that an angle opposite to the longest side in a scalene triangle is greater than $60^{\circ}$.

In $\Delta ABC$,$AB = 9 \, \text{cm}$ and $BC = 12 \, \text{cm}$. If $x < \text{perimeter of } \Delta ABC < y$,then find the values of $x$ and $y$.

In triangles $ABC$ and $PQR$,$AB = AC$,$\angle C = \angle P$ and $\angle B = \angle Q$. The two triangles are

Prove that the medians of an equilateral triangle are equal.

In $\Delta ABC$ and $\Delta PQR$,$AB = PR$,$BC = RQ$ and $\angle B = \angle R$,then $\Delta ABC \cong \Delta \ldots$

Vedclass Test Series

Exam Paper Generator

Online Exam Module