In Delta ABC and Delta PQR,angle A cong angle | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) Given that in $\Delta ABC$ and $\Delta PQR$,$\angle A = \angle P$ and $\angle B = \angle R$.By the Angle-Angle $(AA)$ similarity criterion,if two

Vedclass · Accepted Answer

$PRQ$

Vedclass · Answer

(A) Given that in $\Delta ABC$ and $\Delta PQR$,$\angle A = \angle P$ and $\angle B = \angle R$.By the Angle-Angle $(AA)$ similarity criterion,if two angles of one triangle are respectively equal to two angles of another triangle,then the two triangles are similar.Since $\angle A$ corresponds to $\angle P$ and $\angle B$ corresponds to $\angle R$,the third angle $\angle C$ must correspond to $\angle Q$ (as the sum of angles in a triangle is $180^{\circ}$).Therefore,the correspondence $ABC \leftrightarrow PRQ$ represents the similarity $\Delta ABC \sim \Delta PRQ$.

In $\Delta ABC$ and $\Delta PQR$,$\angle A \cong \angle P$ and $\angle B \cong \angle R$. Then,the correspondence $ABC \leftrightarrow \ldots$ is a similarity.

Similar Questions

Transversals $t_{1}$ and $t_{2}$ to $l_{1} \parallel l_{2} \parallel l_{3}$ intersect them at $A, B, C$ and $P, Q, R$ respectively. If $AB = 5$,$BC = 8$ and $PQ = 6.5$,find $QR$.

In the given figure,if $PQRS$ is a parallelogram and $AB \parallel PS$,then prove that $OC \parallel SR$.

In $\Delta ABC$,$m \angle B = 90^{\circ}$ and $\overline{BM}$ is an altitude. If $AB = 8$ and $BC = 6$,then $BM = \dots$

In $\Delta ABC$,$m \angle B = 45^{\circ}$ and $\overline{AM}$ is an altitude,$M \in \overline{BC}$. If $BC = 7$ and $AM = 4$,then $AC = \ldots$

In $\Delta ABC$,the bisector of $\angle A$ intersects $\overline{BC}$ at $D$. If $AB : AC = 3 : 4$ and $BD = 4.5$,then $BC = \ldots$

Vedclass Test Series

Exam Paper Generator

Online Exam Module